##### What will you learn in this chapter?
• Trigonometry definition and concept
• Trigonometric ratios of some specific angles
• Trigonometric ratios of complementary angles
##### Exam Connect

Trigonometry is another concept that can be asked in combination with another concept in competitive exams like DUJAT, IPMAT of IIM Indore and IIM Rohtak, as well as in NPAT of Narsee Monjee BBA entrance. Even though sometimes, questions from trigonometry are not asked directly, it can be asked in combination with another concept like derivations, integral calculus, etc.

### Trigonometry

We all have studied about triangles in lower classes. Trigonometry is basically the advanced form of determining a triangle. That means, the study to determine the relationship between the sides and angles of a triangle is known as Trigonometry.

#### Trigonometric Ratios

The first concept that weâ€™ll go through is trigonometric ratios. When it comes to a right angled triangle, the relationship between the sides of a right angled triangle w.r.t its acute angles can be determined. These relationships between the sides is given in a ratio format and are known as Trigonometric Ratios.

The trigonometric ratios of a right-angled triangle can be given in the following way:

sin of âˆ A = side opposite to angle A/hypotenuse = BC/AC

cos of âˆ A = side adjacent to angle A/hypotenuse = AB/AC

tan of âˆ A = side opposite to angle A/side adjacent to angle A = BC/AB

cot of âˆ A = 1/tangent of angle A = AB/BC

sec of âˆ A = 1/cosine of angle A = AC/AB

cosec of âˆ A = 1/sine of angle A = AC/BC

#### Trigonometric Ratios for specific angles

Now, when it comes to specific angles in trigonometry, then these angles are generally defined as 0Â°, 30Â°, 45Â°, 60Â° and 90Â°. However, sometimes it is even extended to 180Â°, 270Â° and 360Â°. The trigonometric ratios for these specific angles are given in the form of a table, which is as follows:

#### Trigonometric Ratios for Complementary angles

When an angle is defined in the form of 90Â°-A, the sides of the triangle w.r.t the angle becomes opposite. That means:

1. Normally, sin A = BC/AC. But the sides becomes opposite when the angle is subtracted from 90Â°, i.e. sin (90Â° -A) = AB/AC
2. Similarly, cos A = AB/AC. So, cos (90Â° -A) = BC/AC
3. Again, tan A = BC/AB. So, tan (90Â° -A) = AB/BC
4. Again, cot A = AB/BC. So, cot (90Â° -A) = BC/AB
5. Similarly, sec A = AC/AB. So, sec (90Â° -A) = AC/BC
6. And, csc A = AC/BC. So, csc (90Â° -A) = AC/AB

Now, from these points, we can deduce the following:

1. sin (90Â°-A) =cos A
2. cos (90Â°-A) =sin A
3. tan (90Â°-A) =cot A
4. cot (90Â°-A) =tan A
5. sec (90Â°-A) =csc A
6. csc 90Â°-A =sec A

These are known as trigonometric ratios for complementary angles. However, these trigonometric ratios can be given for more complementary related angles. These ratios are defined in the following table:

Continue your trigonometry learning with our next article on trigonometric identities and many more topics here.

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